Monday, June 13, 2016

Best Book For CSIR NET Part A (General Aptitude) 2016

Hi, friends for a long time I can not provide you any perpetration material for NET Examination.
You all know that part A of NET Exam paper is common for everyone.Part A has questions related general aptitude. In this part, all questions are related to logical reasoning, graphical analysis, analytical and numerical ability, quantitative comparisons, series formation, puzzles, etc.
 We all now that biology students are mostly week in these type of question, In NET Exam part A is a big reason for disqualification. Part A has 60 questions, and you have to attempt 50 question, and every question will give you 2 marks for the right answer.In this condition, you have to attempt this part very carefully. Most of the biology students gave so much time to part A and got lose in part B.So you have to do preparation for this part. 
And today I am suggesting you best book for general aptitude in low price. I surely tell you that you will archive best marks in part A with this book.

The book is-

CSIR-NET General Aptitude - A New Outlook Paperback – 2016

by-Christy varghese
Price -   299.00 only

click here for buy-
CSIR-NET General Aptitude - A New Outlook 

Product Description
this is the third version of the first-class seller CSIR - NET general Aptitude - a brand new Outlook, thoroughly revised with brought contents and strategy to today's CSIR-net common aptitude query papers. It is important for all science streams - Mathematical Sciences, physical Sciences, Chemical Sciences, lifestyles Sciences and Earth Sciences. The book involves topic-clever distinct idea of all subject matters recounted within the modern day syllabus issued by CSIR, strongly supported by means of matter smart illustrative examples for clear understanding and topic intelligent follow questions. Web aspirants will improvement from the sample practice query papers and the tips, methods and short-cuts for solving speedily.

Other Buyers Reviews About This Book-

1.Two NET checks are over because the first edition of the publication and I've observed that one might without problems answer as a minimum 15 questions partly A simply with the aid of scanning through this guide. A lot of the credit score goes to the well ordered, criss-move presentation of concepts in least phrases as feasible however crystal clear, adopted with the aid of a handful of worked out examples and a set of issues for the reader to check out themselves to get used to the subject in hand. The Book also trains one's analytical abilities and sharpens one's original experience.

2.I feel the author has restrained the scope of this guide to CSIR-NET; this book covers nearly all principal issues to answer basic Aptitude questions for any science subject entrance examination, from Undergraduate level, and will without doubt benefit those who are making ready for GATE/financial institution checks etc. I might in my opinion advocate this book, and its worth every penny you pay for.

3.This can be a rather fine guide. It has all of the previous questions answered from Dec 2012. Unique solutions, cautious and exhaustive choice of themes are the uniqueness of the book. Lots of the feasible issues for aptitude test are covered. Just a few issues a day for five-6 months can do wonders in the net exam. 

Tuesday, June 7, 2016

Solved Previews Question Papers And Modal Paper For Life Science NET Examination 2016

Dear students,
Most of the students do not have last years question papers somewho have do not have a solution to these questions. And NET exam is very near, so everyone wants to get solved question papers. 
So for students demand I am providing you last years some solved and some unsolved question papers with some model question papers. Solve them it may be very helpful for you. Please give your reviews in a comment.







Click here for-

Dear students according to paper pattern Part A is common for every one of general science so please download general science model paper here-


For Best preparation of NET exam read my this article and buy the best book for CSIR UGC NET Life Science Exam 2016


Tuesday, May 31, 2016

The Best Book For Life Science NET Exam 2016

Hello dear students,  
NET/JRF Exam 2016 June exam date is declared and I hope you start your study. We have not the time to read everything in this short period, so you have to read short notes.
Today I refer you the best preparation book for CSIR UGC (NET) Life  Science Exam 2016

About The Book-
Ace The Race Plus: MCQs for CSIR-UGC internet life Sciences is the 2d product after the effective unlock of Ace The Race. The book Ace The Race Plus: MCQs for CSIR-UGC web lifestyles Sciences is a strategically designed booklet comprising of 8000 excessive best multiple option Questions (MCQs). 
Part of the 360-degree prep software series, this product has been designed to achieve success in CSIR-UGC web existence Sciences (JRF & LS) and other lifestyles sciences examinations similar to GATE, DBT-JRF, ICMR-JRF, IISc, TIFR, BARC, ISRO, and DRDO. 
After getting ready the theoretical basis for the duration of the instruction of CSIR-UGC internet lifestyles Sciences, the following and virtually a significant step to be taken forward is to expose the aspirants to skillfully designed questions. To be able to reap this, the team at BioSmart Publications has dedicated more than 25000+ man hours in creating the questions.
Ace The Race - Plus: MCQs for CSIR UGC NET Life Sciences (JRF & LS) (Set of 2 Volumes: Vol 1- 8000 MCQs & Vol 2 - Answers & Explanations) (Set of 2 Volumes: Vol 1- 8000 MCQs & Vol 2 - Answers & Explanations)


For other relevant topics, you may read my previous post

Friday, March 11, 2016

Best free csir net life science notes pdf

Dear Students,
Today I share you a best free pdf e book for life science basics, this free e book is made by department of basic education Republic of South Africa.

this free e book is basically make for 12 th grade of south africa but this book not only contains basic of life sciences but it will also give us:-
1-Memory tips for remember life science terms.
2-Easy notes which clear all of your basics of life science.
3-Give study tips
4-Excellent mind map and mnemonics tips for every life science student.
So this free pdf book is essential and must read for all 12 th to M.sc (life science) students.
If you prepare for csir net life science then this is your first easy pdf notes for csir net life science.
Download it from this link:-
After memorize above basics I recommended to read these 4 books:-
Finally memorize my free capsules of easy life science notes for csir net life science here:-

Tuesday, February 9, 2016

CAPSULE 5-ABOUT STRUCTURAL CHANGES IN CHROMOSOMES

Hello friends, After long time I come with a new capsule. I hope last capsules are helpful for you.
Now I want to say some important things about this capsule. This capsule is very very important for NET EXAMINATION. Not only for NET as well as other exams. Now the question is why this capsule is most important?
The topic of this capsule is hard to understand.
structural changes in chromosome play effective role in genetics.
The questions about this topic is hard so these are important.
I request to students that please read this topic clearly this is relay important for examination.
The last thing is that if you have any problem to understand this capsule so please say me I will provide you a video about structural changes in chromosome and I am sure this topic will clear surely.

click here to download- capsule 5

NOTE-This capsule is not divided in points because this hard to understand.

Tuesday, February 2, 2016

CSIR UGC NET/JRF LIFE SCIENCE DECEMBER 2015 EXAM PAPER AND ANSWER KEY

last December CSIR UGC(Human Resource Development Group Council of Scientific & Industrial Research) organized NET/JRF EXAM on 20th December .This exam was held in three shifts A, B and C.

 For all booklets answer keys are different.
Here I am providing all three booklets official exam papers and answer keys. Candidates check there answer key according there booklet number.

CSIR UGC NET/JRF LIFE SCIENCE DEC. 2015 



DOWNLOAD ANSWER KEY FOR A B AND C BOOKLETS HERE-



Monday, February 1, 2016

CSIR-UGC NET/JRF LIFE SCIENCE EXAM.DECEMBER 2014 SOLVED PAPER WITH DESCRIPTION Q.NO. 91 to 95

Click here for-
86 TO 90 QUESTIONS WITH ANSWER OF CSIR UGC NET/JRF EXAMINATION

Q91.For successful fertilization in sea urchin,interaction between the surface of the egg and acrosomal proteins, specifically a 30.5 kDa protein called bindin, is necessary. The following factors could affect this interaction and prevent fertilization-
1.Removal of egg jelly polysaccharides.
2.Removal of bindin receptors on the egg vitelline membrane.
3.Removal of bindin receptors from the egg jelly.
4.Removal of bindin receptors from a single culster on the vitelline membrane.
Which one or the combination above statements is correct?
(A)1 and 4                                      (B)Only 2
(C)1 and 2                                      (D)Only 3
Answer-B
Description-Bindin is a 30.5kDa (Head of spermatozoa acrosomal protein) is a major protein of sea urchin required for fertilization(interaction with the surface of egg via specific receptor on egg surface)
Removal of bindin receptors on the egg vitelline memb. will affect this interaction and prevent fertilization.

Q92.A mutant embryo of Drosophila in which one of the major sex determining gene.sex lethal, can only undergo default splicing. was allowed to develop. The following statements are towards explaining the determination of sex of the embryo-
1.The embryo will develop into a male fly.
2.The embryo will develop into a female fly.
3.sex lethal gene product directly regulates sex specific alternate splicing of double sex RNA.
4. sex lethal  gene product regulates sex specific splicing of transformer RNA which in turn regulates splicing of double sex RNA.
The correct combination of above statements to explain sex determination of the given embryo is-
(A)1 and 3
(B) 1 and 4
(C)2 and 4
(D) 2 and 3
Answer-B
Description-Sxl-gene is sex lethal gene is a master switch gene for somatic cell determination in D. melanogaster.
In XX animals, Sxl become activated and imposes female development,while in XY animals. Sxl remains inactive and male development ensures.
Therefore,default splicing will inactivate Sxl protein product.Hence male develops.
Also sex lethal is an RNA splicing enzyme whose immediate target is transformer mRNA.Since, Sxl are not transcribed in males, its action on Transformer is restricted to females.
sex lethal acts positively in the functional splicing of transformer mRNA. Transformer is another splicing factor. Hence determines female development fate.

Q93.A two celled embryo made of blastomeres A and B. If the two blastomeres are experientially separated, the A blastomere generates all the cells it would normally make. However the B blastomere in isolation makes only a small fraction of cells it would normally make.Based on the above observations only, which one of the following conclusions is correct?
(A) A blastomere is autonomously specified while B blastomere is conditionally specified.
(B) A blastomere is conditionally specified while B blastomere is autonomously specified.
(C) Descendants of A blastomere are autonomously specified.
(D)Descendants of B blastomere can either be autonomously specified or conditionally specified.
ANSWER-A

94.A mutant was experimentally generated which has wings reduced to haltere like structure. The following statements are put forward regarding this phenotype-
1.ultrabithorex gene ectopically expressed in second thoracic segment.
2. antennapedia gene ectopically  expressed in second thoracic segment.
3.A homeotic mutation.
4. A mutation in gap gene.
The following combination of statements will be most appropriate explaining the molecular basis of mutant phenotype-
(A)1 and 2
(B)2 and 3
(C)3 and 4
(D)1 and 3
ANSWER-D
Description- Ultrabithorax (activated in absence of hunchback protein) Ubx gene found in insects.
In D.melanogaster it is expressed in the 3rd thoracic and 1st abdominal segments and repress wing formation. Ubx gene regulates the decisions regarding the no. of wings and legs.
Homeotic mutation causes tissues to alter their normal differentiation pattern producing integrated structures but in unusual locations.

Q95.Following are certain statements regarding the activities of homeotic genes of classes A,B and C involved in floral organ identity-
1.Activity of A alone specifies sepals.
2.Activity of B alone specifies petals.
3.Activity of B and C form stamens.
4.Activity of C alone specifies carpels.
Which one of the following combinations of above statements is correct?
(A)1,2 and 3
(B)1,2 and 4
(C)2,3 and 4
(D)1,3 and 4
ANSWER-D


Sunday, January 3, 2016

AEROBIC RESPIRATION-KREBS CYCLE

The molecule of pyruvic acid which is made in glycolysis enters in kerbs cycle(if oxygen is present)
Krebs cycle start with aetyl coA so firstly pyruvic acid changed in acetyl coA. For this TPP co-enzyme and Mg++ are important. In this process oxidation and decarboxilation held together so this process called oxidation decarboxilation. For this process pyruvic dehydrogenase complex is important. This complex is group of three enzymes.These enzymes are-
1.Pyruvate decarboxynilase
2Lipoate reductase trans acetylase
3.De hydrolipoate dehydrogenase

Energy yieldduring oxidative decarboxilation-
2 pyruvic acid+2NAD-2 acetyl coA+ 2NADH2
2NADH2- 6ATP

For first step of aerobic respiration click here-GLYCOLYSIS

KREBS CYCLE/TCA  CYCLE/CITRIC ACID CYCLE
Krebs cycle was discovered by Hans Krebs.It occur inside mitochondria.It is a amphibolic path way because it is a comon path wat for protien,lipids catabolism. Acetyl coA functions as sbstrate entrant for Kreb cycle.This cycle complates in 10 steps.These are-


1.Condensation-Acetyl coA combines with oxalo acetate in the presence of citrate synthetase to form citric acid.
Acetyl coA+OAA→citric acid+CoA-Sh

2.Dehydration-Citrate forming Aconitic acid with releasing of water molecule in the presence of aconitase.
Citrate→cis aconitic acid

3.Hydration-cis aconitate is converted into isocitrate with the addition of water in the presence of aconitase.
Cis aconitate+water molecule→Isocitrate

4.Dehydrogenation-Isocitrate is dehydrogenated to oxalosuccinate in the presence of enzyme isocitrate dehydrogenase and Mn++.NADH2 is produced.
isocitrate+NAD+→oxalosuccinate+NADH2

5.Decarboxilation-Oxalosuccinate is decarboxylated to from α-ketoglutarate through enzyme decarboxylase.
Oxalosuccinate α-ketoglutarate

6.Dehydrogenation and Decarboxylation- α-ketoglutarate is both dehydrogenated and decarboxylated by an enzyme complex  α-ketoglutarate dehydrogenase.the enzyme complex contains TPP and lipoic acid.The product combines with coA to from succinyl CoA.
 α-ketoglutarate+CoA+NAD→SuccinylCoA+NADH+H+

7.Formation of ATP/GTP-Succinyl CoA is acted upon by enzyme succinyl thiokinase to form succinate.The reaction release sufficient energy to form ATP or GTP.

Succinyl CoA+GDP/ATP Succinate+CoA+GTP/ATP

8.Dehydrogenation-Succinate undergoes dehydrogenation to form fumarate with the help of a dehydrogenase.FADH2 is produced.

Succinate+FAD→Fumarate+FADH2

9.Hydration-A molecule of water gets added to fumerate to form malate. The enzyme is called fumarase.
Fumarate+H2OMalate

10.Dehydrogenation-Malate is Dehydrogenated or oxidised through the energy of malate dehydrogenase to produce oxaloacetate. Hydrogen is accepted by NADP+NAD+
Malate=NAD(P)+→Oxaloacetate+NAD(P)H+


Oxaloacetate picks up another molecule of activated acetate to repeat the cycle.

A molecule of glucose yields two molecules of NADH2,2ATP and two pyruvate while undergoing glycolysis. The two molecules of pyruvate are completely degraded in Krebs cycle to form 2 molecules of ATP,8NADH2 and 2FADH2.

Energetics of Krebs cycle reaction                                  No. of ATP


1.Pyruvic acid to actyle cova(NAD)                                   3ATP
2.Isocitric aid to oxallosuccinic acid(NAD)                        3ATP
3. α-Ketogutric acid to succinyl cova(NAD)                       3ATP
4.Succinic acid to fumaric acid(FAD)                                2ATP
5.Malic acid to OAA(NAD)                                                3ATP
6.Succinyl coA to succinic acid                                         1ATP
                                                                                           =15ATP
Total ATP produced during
 complate oxidation of Pyruvic acid =2x15=30ATP
                       And during glycolysis=8ATP
                                     TOTAL ATP=38ATP