Thursday, August 13, 2015

CSIR-UGC NET/JRF LIFE SCIENCE EXAM.DECEMBER 2014 SOLVED PAPER WITH DESCRIPTION Q.NO. 11 TO 20

CSIR-UGC NET/JRF LIFE SCIENCE EXAM.DECEMBER 2014 QUETION NO. 1 TO 10 WITH SOLUTION

Q11.Two platforms are separated horizontally by  distance A and vertically by distance B.They are to be connected by a staircase having identical steps.If the minimum permissible step length is a,and a maximum permissible step height is b,the number of step the staircase can have is-
(a)≥B/b                      (b)≤A/a
(c)≥B/b and≤A/a       (d)≤B/b and ≥A/a
Answer-C
Description-Max. permissible step length is a
                    Max. permissible step height is b
Max. number of step in terms of height=B/b
Max. number of steps in terms of length=A/a
so, Max. number of steps ≥B/b and≤A/a

Q12. Ajay,Bunty,Chinu, and Deb were agent, baker,compounder and designer,but not necessarily in the order.Deb told the baker that Chinu is on his way. Ajay is sitting across the designer and net to the compounder.The designer didn't say anything. What is each person's occupation?
(a)Ajay-compounder,Bunty-designer,Chinu-baker,Deb-agent
(b)Ajay-compounder,Bunty-baker,Chinu-agent,Deb-designer
(c)Ajay-baker,Bunty-agent,Chinu-designer,Deb-compounder
(d)Ajay-baker,Bunty-designer,Chinu-agent,Deb-compounder
Answer-D

Q13.Every month the price of a particular commodity falls in this order-
1024,640,400,250,....
What is the next value?
(a)156.25
(b)Approximately 39
(c)64
(d)40
Answer-A
Description-The percentage fall in price=640x100/1024 x100
                                                               =37.5
                    the per cant fall in price
                    37.5=price fall/present price x100
                    37.5=price fall/250x100
                    price fall=93.75
                   Future price=250-93.75
                                      =156.25

Q14.We defina function f(N)=sum of digits of N,expressed as dimal number.e.g..f(137)=1+3+7=141.Evaluate f(273556 )-
(a)10                 (b)18
(c)28                 (d)11
Answer-B
Description-If f(137)=1+3+7=11 then,
             f(273556 )=7+5+6=18
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Q15.A certain day,which is x day before 17th August,is such that 50 days,it was 4x days since March 30th of the same year.What is x?
(a)18              (b)30
(c)22              (d)16
Answer-D

Q16.A mouse has to go from point A to B without retracing any part of the path,and never moving backwards.What is the total number of distinct paths that the mouse may take to go from A to B?
(a)11                    (b)48
(c)72                    (d)24
Answer-B
Description-Total number of distinct paths taken=2x4x3x2=48

Q17.The sum of first n natural numbers with one of them missed is 42.What is the number that was missed?
(a)1                      (b)2
(c)3                      (d)4
Answer-C
Description-Sum of n natural no.=n/2(2a+(n-1)d)
                   where, n=no. of natural no. added
                               a=Initial natural no.
                               d=difference between them
                           Sum=n/2(2x1+(n-1)1)
                                  =n/2(n+1)
             If the missed natural no. was x thus,
                                x+42=n/2(n+1)
       Substituting the value of x which represents missed natural no.
                                 If x=1
                                   1+42=n/2(n+1)
                                   86=n2+n
                                   n2+n-86=0
                                  No solution

                      If x=2

                      = 2+42=n/2(n+1)
                        = 88=n2+n
                        = n2+n-88=0
                           No Solution

                             If x=3

                          =3+42=n/2(n+1)
                          = 90=n2+n
                         =n2+n-90=0
                                   =n=9

                             Ifx=4

                         =4+42=n/2(n+1)
                         =92=n2+n
                         =n2+n-92=0
No solution thus,as x=3 can predict that no. of natural no. are added together so option C is correct.

Q18.A2.2 m wide rectangular steel plate is corrugated as shown in the diagram.Each corrugation is a semicircle in cross section having a diameter of 7cm.What will be the widh of steel after it is cirrugated?

(a)1.4m                 (b)1.6m
(c)0.7m                  (d)1.1m
Answer-A

Q19.If N,E and T are distinct poitive integers such that NxExT=2013,then which of the followongs is the maximum possible sum of N,E and T?

(a)39               (b)2015
(c)675             (d)671
Answer-C

Q20.The areas of the inner circle and the shaded ring are equal.The radii r1 and r2 are related by-

(a)r1=r2            (b)r1=r2√2
(c)r1=r2√3        (d)r1=2r2
Answer-B

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CSIR-UGC NET/JRF LIFE SCIENCE EXAM.DECEMBER 2014 QUETION NO. 21 TO 30 WITH SOLUTION

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