CSIR-UGC NET/JRF LIFE SCIENCE EXAM.DECEMBER 2014 PAPER QUESTION NO. 11 TO 20 WITH SOLUTION
21. Reaction products inhibit catalysis in enzymes by-
(a) covalently binding to the enzyme
(b) altering the enzyme structure
(c) occupying the active site
(d) from a complex with the substrate
Answer-C
Description-If the reaction product is accumulated as it is not utilized within the chemical reaction pathway so will occupy the active site of the enzyme hence inhibiting it.
Q22. Chirality of DNA is due to-
(a)the bases
(b)base stacking
(c) hydrogen bonds between bases
(d) deoxyribosome
Answer-D
Description- Chirality refers to the ability of a molecules to rotate the plane polarized light.
For a compound to be chiral it must possess all the valency groups to be different from each other.
Q23. Which of the following statements regarding membrane transport is false?
(a)Poler and charged solutes will not cross cell membranes effectively without specific protein carriers
(b)Each protein carrier will only bind and transport one (or a few very similar) type of solute
(c) Sugars such as glucose are always transported by active transport rather then by facilitated diffusion carriers
(d)Ions are typically transported by special proteins that from membrane channels
Answer-C
Description- Sugar such as glucose are transported through facilitated diffusion mediated by glucose transporter (GLUT), thus statement 3 is false.
Q24.What will happen if histones are depleted from a metaphase chromosome and viewd under a transmission electron microscope?
(a)30mm chromatin fibres will be observed
(b) 10nm chromatin fibres will be observed
(c) A scaffold and a huge number of loops of DNA fibres will be observed
(d) A huge number of loops of DNA fibres without scaffold will be obsereved
Answer-C
Description-Scaffold proteins along with histones are responsible for maintaining the structure integrity of the DNA. If histones are lost or depleted then,DNA will be observed in the form of large no. of loops.
Q25.In proteins, hydrogen bonds from as follows- Donor (D)-H....Acceptor if the angle between D-H and A is-
(a)<90 Degree (b)180 Degree
(c)180 Degree (d)120 Degree
Answer-B
Description- The most stable hydrogen bonds are formed when the Doner-Hydrogen and acceptor are in front of each other i.e. at an angle of 180 Degree
READ 1 TO 10 QUESTION ANSWER ON THIS LINK-
1-10 QUESTION ANSWER WITH SOLUTION
Q26.Leader sequence in some of the protozoan parasites is transcribed elsewhere in the parasite genome and gets joined with several transcripts to make the functional RNA. The joining of the two transcripts occur by the process of-
(a) alternate splicing (b) trans splicing
(c)ligation (d)RNA editing
Answer-B
Q27. Small nuclear RNAs used to process and chemically modify rRNAs are called-
(a)Sca RNAs (b)Si RNA s
(c)Sno RNAs (d)Sn RNAs
Answer-C
Description-Sno RNA (small nucleolar RNA) participate in the processing and modification of r RNA
Q28.Protein motive force during oxidative phosphorylation is generated in mitochondria by-
(a) Exchanging protons for sodium ions
(b)pumping protons out into intermembrane space
(c)pumping hydroxyl ions into the mitochondria
(d)hydrolysis of ATP
Answer-B
Description- The proton motive force during oxidative phosphorylation is generated in mitochondria by the movement of [H+] across the inner mitochondrial membrane mediated by electron transport system.
Q29. During replication the RNA primer is degraded by the 5'-3' exonuclease activity of-
(a)RNAase H1(ribonuclease H1)
(b) FEN-1 (flap endonuclease 1)
(c) Topoisomererase II B
(d) DNA polymerase ɣ
Answer-B
Description- During DNA Replication FEN-1 degades RNA primer by its 5'-3' exo nuclease activity.
Q30.Which one of the following statements about eukaryotic translation is not true?
(a)ribosome binding site on m RNA is called Kozak consensus sequences
(b)initator tRNA is tRNAif-met
(c)initator amino acid is nethionine
(d)translocation factor is eEF2
Answer-B
Description-During E.K. translation initiator t-RNA is tRNA met and not tRNAif-met
click here for-
CSIR-UGC NET/JRF LIFE SCIENCE EXAM.DECEMBER 2014 PAPER QUESTION NO. 31 TO 40 WITH SOLUTION
21. Reaction products inhibit catalysis in enzymes by-
(a) covalently binding to the enzyme(b) altering the enzyme structure
(c) occupying the active site
(d) from a complex with the substrate
Answer-C
Description-If the reaction product is accumulated as it is not utilized within the chemical reaction pathway so will occupy the active site of the enzyme hence inhibiting it.
Q22. Chirality of DNA is due to-
(a)the bases
(b)base stacking
(c) hydrogen bonds between bases
(d) deoxyribosome
Answer-D
Description- Chirality refers to the ability of a molecules to rotate the plane polarized light.
For a compound to be chiral it must possess all the valency groups to be different from each other.
Q23. Which of the following statements regarding membrane transport is false?
(a)Poler and charged solutes will not cross cell membranes effectively without specific protein carriers
(b)Each protein carrier will only bind and transport one (or a few very similar) type of solute
(c) Sugars such as glucose are always transported by active transport rather then by facilitated diffusion carriers
(d)Ions are typically transported by special proteins that from membrane channels
Answer-C
Description- Sugar such as glucose are transported through facilitated diffusion mediated by glucose transporter (GLUT), thus statement 3 is false.
Q24.What will happen if histones are depleted from a metaphase chromosome and viewd under a transmission electron microscope?
(a)30mm chromatin fibres will be observed
(b) 10nm chromatin fibres will be observed
(c) A scaffold and a huge number of loops of DNA fibres will be observed
(d) A huge number of loops of DNA fibres without scaffold will be obsereved
Answer-C
Description-Scaffold proteins along with histones are responsible for maintaining the structure integrity of the DNA. If histones are lost or depleted then,DNA will be observed in the form of large no. of loops.
Q25.In proteins, hydrogen bonds from as follows- Donor (D)-H....Acceptor if the angle between D-H and A is-
(a)<90 Degree (b)180 Degree
(c)180 Degree (d)120 Degree
Answer-B
Description- The most stable hydrogen bonds are formed when the Doner-Hydrogen and acceptor are in front of each other i.e. at an angle of 180 Degree
READ 1 TO 10 QUESTION ANSWER ON THIS LINK-
1-10 QUESTION ANSWER WITH SOLUTION
Q26.Leader sequence in some of the protozoan parasites is transcribed elsewhere in the parasite genome and gets joined with several transcripts to make the functional RNA. The joining of the two transcripts occur by the process of-
(a) alternate splicing (b) trans splicing
(c)ligation (d)RNA editing
Answer-B
Q27. Small nuclear RNAs used to process and chemically modify rRNAs are called-
(a)Sca RNAs (b)Si RNA s
(c)Sno RNAs (d)Sn RNAs
Answer-C
Description-Sno RNA (small nucleolar RNA) participate in the processing and modification of r RNA
Q28.Protein motive force during oxidative phosphorylation is generated in mitochondria by-
(a) Exchanging protons for sodium ions
(b)pumping protons out into intermembrane space
(c)pumping hydroxyl ions into the mitochondria
(d)hydrolysis of ATP
Answer-B
Description- The proton motive force during oxidative phosphorylation is generated in mitochondria by the movement of [H+] across the inner mitochondrial membrane mediated by electron transport system.
Q29. During replication the RNA primer is degraded by the 5'-3' exonuclease activity of-
(a)RNAase H1(ribonuclease H1)
(b) FEN-1 (flap endonuclease 1)
(c) Topoisomererase II B
(d) DNA polymerase ɣ
Answer-B
Description- During DNA Replication FEN-1 degades RNA primer by its 5'-3' exo nuclease activity.
Q30.Which one of the following statements about eukaryotic translation is not true?
(a)ribosome binding site on m RNA is called Kozak consensus sequences
(b)initator tRNA is tRNAif-met
(c)initator amino acid is nethionine
(d)translocation factor is eEF2
Answer-B
Description-During E.K. translation initiator t-RNA is tRNA met and not tRNAif-met
click here for-
CSIR-UGC NET/JRF LIFE SCIENCE EXAM.DECEMBER 2014 PAPER QUESTION NO. 31 TO 40 WITH SOLUTION
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